(8n^2+41n+41)/(n+4)

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Solution for (8n^2+41n+41)/(n+4) equation: 


D( n )

n+4 = 0

n+4 = 0

n+4 = 0

n+4 = 0 // - 4

n = -4

n in (-oo:-4) U (-4:+oo)

(8*n^2+41*n+41)/(n+4) = 0

8*n^2+41*n+41 = 0

8*n^2+41*n+41 = 0

DELTA = 41^2-(4*8*41)

DELTA = 369

DELTA > 0

n = (369^(1/2)-41)/(2*8) or n = (-369^(1/2)-41)/(2*8)

n = (3*41^(1/2)-41)/16 or n = (-3*41^(1/2)-41)/16

(n-((-3*41^(1/2)-41)/16))*(n-((3*41^(1/2)-41)/16)) = 0

((n-((-3*41^(1/2)-41)/16))*(n-((3*41^(1/2)-41)/16)))/(n+4) = 0

( n-((-3*41^(1/2)-41)/16) )

n-((-3*41^(1/2)-41)/16) = 0 // + (-3*41^(1/2)-41)/16

n = (-3*41^(1/2)-41)/16

( n-((3*41^(1/2)-41)/16) )

n-((3*41^(1/2)-41)/16) = 0 // + (3*41^(1/2)-41)/16

n = (3*41^(1/2)-41)/16

n in { (-3*41^(1/2)-41)/16, (3*41^(1/2)-41)/16 }

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